![]() As noted in the comment -w is a GNU extension. ![]() The test is that the matching substring must either be at the beginning of the line, or preceded by a non-word constituent character. But couldn't able to get the actual required output. Select only those lines containing matches that form whole words. The grep command's -w option is explained in the man page as searching for "the expression as a word as if surrounded by \" and it does just that.I'm trying to identify exact match of a string in line. If you want to find instances of "I want cats" in a large file of personal aspirations while avoiding "I want catsup", either of these commands would work just fine: $ cat wish-list The -w and \ options for selecting whole words also work for phrases. Here an example of the lines: 9606 ENSP00000239223 DUSP1 BLAST 9606 ENSP00000239223 DUSP1-001 Ensembl I want to retrieve the first line but not the second one. Tutorials, references, and examples are constantly reviewed to avoid errors, but we cannot warrant full correctness of all content. But I have tried below commands but no luck. I need to extract all the lines which contains the exact word 'DUSP1'. If you enter one search term, only files that contain the exact term are returned with only whole word matches. Of you do not desire to have the filename displayed use the -h (-no-filename) option in addition to remove them. w, -word-regexp Select only those lines containing. You need to use the -o (or -only-matching ) option in your command line option. Besides, these options wouldn't have a chance of finding your target text if it appeared inside quotes or following by some character other than a blank while still clearly a whole word: $ grep -w cat program.c Now with grep we have an argument ( -w ) which is used to grep for exact match of whole word from a file. This sure beats looking for a whole word by grepping for " cat ", "^cat " and " cat$". Examples of such power file/text searching tools might be: GrepWin. grep -w 1.2.3.4 testfile.csv 1.2.3.4,Jim,Jonson,000000 1.2.3.4.5,George,Doe,FFFFF How can I make it match exactly and only the specific word In this example only 1.2.3.4. Similarly, it must be either at the end of the line or followed by a non-word constituent character. ![]() $ grep "\" /usr/dict/wordsĮither of these tricks will keep you from getting "catharsis" and "catatonic" when you only want lines containing "cat". Match whole word only: if checked, searches will only match if the result is a. w, -word-regexp Select only those lines containing matches that form whole words. Don't forget to put your expression in quotes as shown. So if you wish for the command to be portable then youll have to do. However, this will be non-portable, since POSIX grep lacks the -w flag and neither basic nor extended regular expressions support word boundaries. You can also use the regular expression \ delimiters that select whole words. If youre using GNU grep then you can use the -w or -word-regexp flag, or wrap the regex with word boundaries: grep bHb. ![]()
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